I received some taster ratings from the champagne party we attended last week. I joined the raw ratings with the bottle information to create a single aggregated dataset. This is a 'non-normal' form, but simplest to distribute. Here is a taste:

library(dplyr)
library(readr)
library(knitr)
champ <- read_csv('../data/champagne_ratings.csv')
champ %>% select(winery,purchase_price_per_liter,raternum,rating) %>% 
    head(8) %>% kable(format='markdown')
winery purchase_price_per_liter raternum rating
Barons de Rothschild 80.00000 1 10
Onward Petillant Naturel 2014 Malavasia Bianca 33.33333 1 4
Chandon Rose Method Traditionnelle 18.66667 1 8
Martini Prosecco from Italy 21.32000 1 8
Roederer Estate Brut 33.33333 1 8
Kirkland Asolo Prosecco Superiore 9.32000 1 7
Champagne Tattinger Brute La Francaise 46.66667 1 6
Schramsberg Reserver 2001 132.00000 1 6

Recall that the rules of the contest dictate that the average rating of each bottle was computed, then divided by 25 dollars more than the price (presumably for a 750ml bottle). Depending on whether the average ratings were compressed around the high end of the zero to ten scale, or around the low end, one would wager on either the cheapest bottles, or more moderately priced offerings. (Based on my previous analysis, I brought the Menage a Trois Prosecco, rated at 91 points, but available at Safeway for 10 dollars.) It is easy to compute the raw averages using dplyr:

avrat <- champ %>% 
    group_by(winery,bottle_num,purchase_price_per_liter) %>%
    summarize(avg_rating=mean(rating)) %>%
    ungroup() %>%
    arrange(desc(avg_rating))
avrat %>% head(8) %>% kable(format='markdown')
winery bottle_num purchase_price_per_liter avg_rating
Desuderi Jeio 4 22.66667 6.750000
Gloria Ferrer Sonoma Brut 19 20.00000 6.750000
Roederer Estate Brut 12 34.66667 6.642857
Charles Collin Rose 34 33.33333 6.636364
Roederer Estate Brut 13 33.33333 6.500000
Gloria Ferrer Sonoma Brut 11 21.33333 6.400000
Kirkland Asolo Prosecco Superiore 16 9.32000 6.375000
Mumm Napa Brut Rose 24 26.66667 6.285714

The average ratings range between 3.6666667 and 6.75, so based on my previous analysis, one expects that the winner will be moderately priced, around 7 to 12 dollars in price. But something funny happened: the average ratings do not appear to be positively correlated with cost. Consider the Kendall \(\tau\) measure of correlation, which tests for the presence of a monotonic relationship between paired observations:

cor(avrat$avg_rating,avrat$purchase_price_per_liter,method='kendall')
## [1] -0.06176777

You can check for significance (only if you're a Frequentist) using the cor.test function. There are a number of issues around this, however:

  • Because of the design of this 'experiment', the errors in the taster ratings are not independent. This occurs because idiosyncratic rater preferences affect some champagnes more than others.
  • Similarly, the errors in ratings are heteroskedastic, since some champagnes were rated by more raters than others.
  • As a practical matter, there are ties in the average ratings, so cor.test will complain unless you read the man page and tweak the default settings at your own peril.

Modulo these warnings, it is hard to see the negative \(\tau\) as evidence in favor of a positive relationship between perceived tastiness and price.

Give me a Z?

Since inter-rater reliability is likely to be a problem (I intentionally shifted my average rating downward to increase my own chances of winning, an attack possible in this experiment even under taster blinding), I also tried to normalize ratings for the rater's bias. So I subtract each rater's mean rating, then compute bottle averages. I would have computed a Z-score, but many of the raters tasted fewer than 10 champagnes, making the standard deviations unreliable. Under this adjusted average, the top bottles do not change much, but notice that the duplicated Gloria Ferrer Sonoma Brut bottles have closer adjusted ratings.

avrat <- champ %>%
    group_by(raternum) %>%
    mutate(rating=rating-mean(rating)) %>%
    ungroup() %>%
    group_by(winery,common_name,bottle_num,purchase_price_per_liter) %>%
    summarize(adj_rating=mean(rating)) %>%
    ungroup() %>%
    left_join(avrat %>% select(bottle_num,avg_rating),by='bottle_num') %>%
    arrange(desc(adj_rating)) 

avrat %>% select(winery,bottle_num,purchase_price_per_liter,adj_rating) %>%
    arrange(desc(adj_rating)) %>%
    head(8) %>% kable(format='markdown')
winery bottle_num purchase_price_per_liter adj_rating
Desuderi Jeio 4 22.66667 1.5516168
Gloria Ferrer Sonoma Brut 11 21.33333 0.9608738
Gloria Ferrer Sonoma Brut 19 20.00000 0.9151328
Roederer Estate Brut 13 33.33333 0.9002145
Gloria Ferrer Blanc De Blancs 20 26.65333 0.8590897
Mumm Napa Brut Rose 24 26.66667 0.8302900
Kirkland Asolo Prosecco Superiore 16 9.32000 0.8048640
Piper Sonoma Blanc de Blancs 26 15.98667 0.7445296

Kendall's \(\tau\) is now even more damning of a positive relationship between price and 'tastiness'. I will not show the results of cor.test, since the assumptions of that test are even more questionable.

cor(avrat$adj_rating,avrat$purchase_price_per_liter,method='kendall')
## [1] -0.1503823

Get Me an Expert!

Remember that my entire strategy for winning this contest was predicated on using the 'expert' ratings, publicly available, to predict ratings. Could I have missed this antipathy towards price? Let's check the Kendall \(\tau\) for the 'pro' ratings:

pros <- read_csv('../data/champagne.csv')
pros$pro_rating <- rowMeans(pros[,c('WS','WE','WandS','WW','TP','JS','ST')],na.rm=TRUE)
cor(pros$pro_rating,pros$price_per_liter,use='complete.obs',method='kendall')
## [1] 0.5944033

Let us stipulate that this value is significantly positive. There are two possible interpretations for this outcome, one of which seems like a total conspiracy theory:

  1. Expert tasters are better able to taste true quality in Champagne.
  2. Experts are not blind to the price of what they taste, and the entire purpose of ratings is to justify spending more on a bottle of Champagne than you might otherwise.

I won't say which is the conspiracy theory. Let us, however, look at the pro ratings versus our taster ratings (the 'hoi polloi'), Z-scoring the ratings for both groups. There does seem to be a serious mismatch between these two functions of price:

group_ratings <- avrat %>% 
    select(purchase_price_per_liter,adj_rating) %>%
    rename(price=purchase_price_per_liter) %>%
    mutate(rater='hoi polloi') %>%
    rbind(pros %>% select(price_per_liter,pro_rating) %>% 
        rename(price=price_per_liter,adj_rating=pro_rating) %>%
        mutate(rater='expert')) %>%
    group_by(rater) %>%
    mutate(adj_rating=(adj_rating - mean(adj_rating,na.rm=TRUE))/sd(adj_rating,na.rm=TRUE))

library(ggplot2)
ph <- ggplot(group_ratings,aes(x=price,y=adj_rating,group=rater,colour=rater)) + 
    geom_point() +
    stat_smooth() + 
    scale_x_log10() + 
    labs(x='price per liter',y='rating (Z)')
print(ph)

plot of chunk champrat_one

Computing the Kendall \(\tau\) on bottles which appear in both experiments would be enlightening, but there are actually very few in the intersection, due to mismatches in vintage and style, and also the mismatch in price points of the two groups. I think it should not be surprising that the cheapest sparkling wines scored relatively well among real tasters--a cheaper product should have broad appeal in order to make up for the presumably smaller margins.

Conclusions

If you are on the market for a bottle of Champagne, say to bring to a New Year's party, here are my suggestions based on the limited data available:

  • Spend around 13 dollars for a 750ml bottle.
  • If I had to guess, among the cheapest sparkling wines, the drier style is likely to be more palatable than the sweeter styles.
  • If you feel embarrassed bringing a cheap bottle to someone's party, buy two bottles. Or, better, bring flowers too.